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[FEA]: Require ct.barrier for multi stage kernels #37
Is this a new feature, an improvement, or a change to existing functionality?
New Feature
How would you describe the priority of this feature request?
High
Please provide a clear description of problem this feature solves
In CUDA programming, we use atomic methods or cooperative groups to synchronize execution across blocks.
cutile could provide a similar mechanism to help developers write complex multi-stage kernels in a simpler way.
Feature Description
Example:
importtorchimportcuda.tileasct@ct.kerneldefdevice_norm(
x: ct.Array, y: ct.Array, workspace: ct.Array,
tile_size: ct.Constant, p: ct.Constant):
# create a barrier on global memory, except p blocks to reach it.barrier=ct.barrier(p=p)
block_id=ct.bid(0)
tile=ct.load(x, index=(block_id, 0), shape=(1, tile_size))
mean=ct.sum(tile) /tile_sizect.atomic_add(workspace, (0, ), mean)
# wait until p blocks to reach herebarrier.wait()
global_mean=ct.load(workspace, (0, ), (1, ))
global_mean=global_mean/ptile=tile-global_meanct.store(y, (block_id, ), (tile_size, ))
Describe your ideal solution
Provide ct.barrier, or a similar feature, to make it easier for developers to write applications that require block-level synchronization.
There are multiple ways to implement ct.barrier:
Allocate a region in global memory for synchronization, and let each block atomically increment a counter when it reaches the barrier.
Use cooperative groups.
Describe any alternatives you have considered
No response
Additional context
No response
Contributing Guidelines
I agree to follow cuTile Python's contributing guidelines
I have searched the open feature requests and have found no duplicates for this feature request
Activity
blinxt commentedon Jan 8, 2026
@ZhangZhiPku Thank you for your interest and request. We'll take it into consideration.
Meanwhile, here's how you can implement barrier functionality with existing atomic operations.
brycelelbach commentedon May 25, 2026
Unfortunately we don't have any way to emulate a backoff, right?