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// Source : https://oj.leetcode.com/problems/zigzag-conversion/

// Author : Hao Chen

// Date : 2014-07-17

/**********************************************************************************

* The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this:

* (you may want to display this pattern in a fixed font for better legibility)

* P A H N

* A P L S I I G

* Y I R

* And then read line by line: "PAHNAPLSIIGYIR"

* Write the code that will take a string and make this conversion given a number of rows:

* string convert(string text, int nRows);

* convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".

**********************************************************************************/

#include <iostream>

#include <vector>

#include <string>

using namespace std;

string convert(string s, int nRows) {

//The cases no need to do anything

if (nRows<=1 || nRows>=s.size()) return s;

vector<string> r(nRows);

int row = 0;

int step = 1;

for(int i=0; i<s.size(); i ++) {

if (row == nRows-1) step = -1;

if (row == 0) step = 1;

//cout << row <<endl;

r[row] += s[i];

row += step;

}

string result;

for (int i=0; i<nRows; i++){

result += r[i];

}

return result;

}

int main(int argc, char**argv){

string s;

int r;

s = "PAYPALISHIRING";

r = 3;

cout << s << " : " << convert(s, 3) << endl;

}

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