@@ -33,28 +33,65 @@
 
     // Array.prototype.filter()
     // 1. Filter the list of inventors for those who were born in the 1500's
+    const bornIn50s = inventors.filter(inventor => inventor.year >= 1500 && inventor.year < 1600);
+    console.table(bornIn50s);
 
     // Array.prototype.map()
     // 2. Give us an array of the inventors' first and last names
+    const names = inventors.map(inventor => `${inventor.first} ${inventor.last}`);
+    console.log(names);
 
     // Array.prototype.sort()
     // 3. Sort the inventors by birthdate, oldest to youngest
+    const sortedInventors = inventors.sort((a, b) => a.year > b.year ? 1 : -1);
+    console.table(sortedInventors);
 
     // Array.prototype.reduce()
     // 4. How many years did all the inventors live?
+    const totalYears = inventors.reduce((total, inventor) => {
+        return total + (inventor.passed - inventor.year);
+    }, 0);
+    console.log(totalYears);
 
     // 5. Sort the inventors by years lived
+    const sortedOldest = inventors.sort((inventor1, inventor2) => {
+      const inventor1Age = inventor1.passed - inventor1.year;
+      const inventor2Age = inventor2.passed - inventor2.year;
+      return inventor1Age > inventor2Age ? -1 : 1;
+    });
+    console.table(sortedOldest);
 
     // 6. create a list of Boulevards in Paris that contain 'de' anywhere in the name
     // https://en.wikipedia.org/wiki/Category:Boulevards_in_Paris
 
+    // const category = document.querySelector('.mw-category');
+    // const links = Array.from(category.querySelectorAll('a'));
+    //
+    // const de = links
+    //            .map(link => link.textContent)
+    //            .filter(boulevard => boulevard.includes('de'));
 
     // 7. sort Exercise
     // Sort the people alphabetically by last name
+    const alpha = people.sort((lastOne, nextOne) => {
+      const [aLast, aFirst] = lastOne.split(', ');
+      const [bLast, bFirst] = nextOne.split(', ');
+      return aLast > bLast ? 1 : -1;
+    });
+    console.log(alpha);
 
     // 8. Reduce Exercise
     // Sum up the instances of each of these
     const data = ['car', 'car', 'truck', 'truck', 'bike', 'walk', 'car', 'van', 'bike', 'walk', 'car', 'van', 'car', 'truck' ];
+    const transporation = data.reduce((obj, item) => {
+      if (!obj[item]) {
+        obj[item] = 1;
+      } else {
+        obj[item]++;
+      }
+      return obj;
+    }, {});
+    console.log(transporation);
 
   </script>
 </body>