@@ -11,6 +11,7 @@
     // ## Array Cardio Day 1
 
     // Some data we can work with
+    // REPEAT THSES UNTIL CONFIDENT AND ABLE TO GO TO A WEBSITE AND REPLICATE
 
     const inventors = [
       { first: 'Albert', last: 'Einstein', year: 1879, passed: 1955 },
@@ -34,32 +35,79 @@
       'Berne, Eric', 'Berra, Yogi', 'Berry, Wendell', 'Bevan, Aneurin', 'Ben-Gurion, David', 'Bevel, Ken', 'Biden, Joseph', 'Bennington, Chester', 'Bierce, Ambrose',
       'Billings, Josh', 'Birrell, Augustine', 'Blair, Tony', 'Beecher, Henry', 'Biondo, Frank'
     ];
-    
+
     // Array.prototype.filter()
     // 1. Filter the list of inventors for those who were born in the 1500's
+    const fifteen = inventors.filter(function(inventor) {
+      if(inventor.year >= 1500 && inventor.year < 1600) {
+        return true; //keeps the ones that are true
+      }
+    });
+    console.table(fifteen);
 
     // Array.prototype.map()
     // 2. Give us an array of the inventors first and last names
+    const fullNames = inventors.map(inventor => inventor.first + ' ' + inventor.last);
+    console.log(fullNames);
+    // another way to do it const fullNames = inventors.map(inventor => `${inventor.first}` `$inventor.last`);
 
     // Array.prototype.sort()
     // 3. Sort the inventors by birthdate, oldest to youngest
+    // const ordered = inventors.sort(function(firstPerson, secondPerson) {
+    //   if(firstPerson.year > secondPerson.year) {
+    //     return 1;
+    //   } else {
+    //     return -1;
+    //   }
+    // });
+    const ordered = inventors.sort((a, b) => a.year > b.year ? 1 : -1);
+
+    console.table(ordered);
 
     // Array.prototype.reduce()
     // 4. How many years did all the inventors live all together?
+    const totalYears = inventors.reduce((total, inventor) => {
+      return total + (inventor.passed - inventor.year);
+    }, 0);
+    console.log(totalYears);
 
     // 5. Sort the inventors by years lived
-
+    const oldest = inventors.sort(function(a, b) {
+      const lastGuy = a.passed - a.year;
+      const nextGuy = b.passed - b.year;
+      return lastGuy > nextGuy ? -1 : 1;
+    });
+    console.table(oldest);
     // 6. create a list of Boulevards in Paris that contain 'de' anywhere in the name
     // https://en.wikipedia.org/wiki/Category:Boulevards_in_Paris
-
+    //code run in the browser
+    // const category = document.querySelector('.mw-category');
+    // const links = Array.from(category.querySelectorAll('a'));
+    // const de = links
+    //               .map(link => link.textContent)
+    //               .filter(streetName => streetName.includes('de'));
 
     // 7. sort Exercise
     // Sort the people alphabetically by last name
+    const alpha = people.sort(function(lastOne, nextOne) {
+      const [aLast, aFirst] = lastOne.split(', ');
+      const [bLast, bFirst] = nextOne.split(', ');
+      return aLast > bLast ? 1 : -1;
+    });
+    console.log(alpha);
 
     // 8. Reduce Exercise
     // Sum up the instances of each of these
     const data = ['car', 'car', 'truck', 'truck', 'bike', 'walk', 'car', 'van', 'bike', 'walk', 'car', 'van', 'car', 'truck' ];
 
+    const transportation = data.reduce(function(obj, item) {
+      if(!obj[item]){
+        obj[item] = 0; //
+      }
+      obj[item]++; //iterates here
+      return obj;
+    }, {}); //<-- the empty {} are a blank object that we start with. The iterate and count the amount of each object is present in the array data
+    console.log(transportation);
   </script>
 </body>
 </html>